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Grade
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Date
Questions20
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1

Find the area of given Circle

9 in

2

Find the area of given Square

8 in8 in8 in8 in

3

Find the area of given Right Triangle

9 in8 in

4

Find the area of given Rectangle

8 in2 in8 in2 in

5

Find the area of given Right Triangle

8 in3 in

6

Find the area of given Rectangle

9 in8 in9 in8 in

7

Find the area of given Circle

8 in

8

Find the area of given Square

5 in5 in5 in5 in

9

Find the area of given Right Triangle

8 in2 in

10

Find the area of given Rectangle

4 in3 in4 in3 in

11

Find the perimeter of given Triangle

7 in7 in3 in

12

Find the perimeter of given Rectangle

8 in2 in8 in2 in

13

Find the perimeter of given Pentagon

6 in6 in6 in6 in6 in

14

Find the perimeter of given Circle

8 in

15

Find the perimeter of given Square

8 in8 in8 in8 in

16

Find the perimeter of given Circle

9 in

17

Find the perimeter of given Trapezoid

5 in10 in9 in4 in

18

Find the perimeter of given Rectangle

5 in2 in5 in2 in

19

Find the perimeter of given Parallelogram

4 in2 in4 in2 in

20

Find the perimeter of given Square

10 in10 in10 in10 in

Answers Key

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1

Find the area of given Circle

9 in

Area = 254.47 in_{2}

Solution

Area of the circle = π x r^{2}

Radius (r) = 9 in

Area = 3.14 x 9 x 9 ; where π = 3.14

Area = 254.47 in^{2}

Radius (r) = 9 in

Area = 3.14 x 9 x 9 ; where π = 3.14

Area = 254.47 in

2

Find the area of given Square

8 in8 in8 in8 in

Area = 64 in_{2}

Solution

Area of the square = side^{2}

Side = 8 in

Area = 8 x 8

Area = 64 in^{2}

Side = 8 in

Area = 8 x 8

Area = 64 in

3

Find the area of given Right Triangle

9 in8 in

Area = 36 in_{2}

SolutionBase (b) = 8 in

Height (h) = 9 inArea =36 in ^{2}

Area of triangle =

12

x b x h

Height (h) = 9 in

Area =

12

x 8 x 9

4

Find the area of given Rectangle

8 in2 in8 in2 in

Area = 16 in_{2}

Solution

Area of the Rectangle = l x b

Length (l) = 8 in

Breadth (b) = 2 in

Area = 8 x 2

Area = 16 in^{2}

Length (l) = 8 in

Breadth (b) = 2 in

Area = 8 x 2

Area = 16 in

5

Find the area of given Right Triangle

8 in3 in

Area = 12 in_{2}

SolutionBase (b) = 3 in

Height (h) = 8 inArea =12 in ^{2}

Area of triangle =

12

x b x h

Height (h) = 8 in

Area =

12

x 3 x 8

6

Find the area of given Rectangle

9 in8 in9 in8 in

Area = 72 in_{2}

Solution

Area of the Rectangle = l x b

Length (l) = 9 in

Breadth (b) = 8 in

Area = 9 x 8

Area = 72 in^{2}

Length (l) = 9 in

Breadth (b) = 8 in

Area = 9 x 8

Area = 72 in

7

Find the area of given Circle

8 in

Area = 201.06 in_{2}

Solution

Area of the circle = π x r^{2}

Radius (r) = 8 in

Area = 3.14 x 8 x 8 ; where π = 3.14

Area = 201.06 in^{2}

Radius (r) = 8 in

Area = 3.14 x 8 x 8 ; where π = 3.14

Area = 201.06 in

8

Find the area of given Square

5 in5 in5 in5 in

Area = 25 in_{2}

Solution

Area of the square = side^{2}

Side = 5 in

Area = 5 x 5

Area = 25 in^{2}

Side = 5 in

Area = 5 x 5

Area = 25 in

9

Find the area of given Right Triangle

8 in2 in

Area = 8 in_{2}

SolutionBase (b) = 2 in

Height (h) = 8 inArea =8 in ^{2}

Area of triangle =

12

x b x h

Height (h) = 8 in

Area =

12

x 2 x 8

10

Find the area of given Rectangle

4 in3 in4 in3 in

Area = 12 in_{2}

Solution

Area of the Rectangle = l x b

Length (l) = 4 in

Breadth (b) = 3 in

Area = 4 x 3

Area = 12 in^{2}

Length (l) = 4 in

Breadth (b) = 3 in

Area = 4 x 3

Area = 12 in

11

Find the perimeter of given Triangle

7 in7 in3 in

Perimeter = 17 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

side 1 = 7 in

side 2 = 7 in

side 3 = 3 in

Perimeter = 7 + 7 + 3

∴ Perimeter = 17 in

side 1 = 7 in

side 2 = 7 in

side 3 = 3 in

Perimeter = 7 + 7 + 3

∴ Perimeter = 17 in

12

Find the perimeter of given Rectangle

8 in2 in8 in2 in

Perimeter = 20 in

Solution

Perimeter of a Rectangle = 2(l+b)

Length (l) = 8 in

Breadth (b) = 2 in

Perimeter = 2 x (8 + 2)

∴ Perimeter = 20 in

Length (l) = 8 in

Breadth (b) = 2 in

Perimeter = 2 x (8 + 2)

∴ Perimeter = 20 in

13

Find the perimeter of given Pentagon

6 in6 in6 in6 in6 in

Perimeter = 30 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

Side = 6 in

Perimeter = 6 + 6 + 6 + 6 + 6

∴ Perimeter = 30 in

Side = 6 in

Perimeter = 6 + 6 + 6 + 6 + 6

∴ Perimeter = 30 in

14

Find the perimeter of given Circle

8 in

Perimeter = 50.27 in

Solution

Perimeter of a circle = 2 x π x r

Radius (r) = 8 in

Perimeter = 2 x 3.14 x 8 ; where π = 3.14

∴ Perimeter = 50.27 in

Radius (r) = 8 in

Perimeter = 2 x 3.14 x 8 ; where π = 3.14

∴ Perimeter = 50.27 in

15

Find the perimeter of given Square

8 in8 in8 in8 in

Perimeter = 32 in

Solution

Perimeter of a square = 4 x side

side = 8 in

Perimeter = 4 x 8

∴ Perimeter = 32 in

side = 8 in

Perimeter = 4 x 8

∴ Perimeter = 32 in

16

Find the perimeter of given Circle

9 in

Perimeter = 56.55 in

Solution

Perimeter of a circle = 2 x π x r

Radius (r) = 9 in

Perimeter = 2 x 3.14 x 9 ; where π = 3.14

∴ Perimeter = 56.55 in

Radius (r) = 9 in

Perimeter = 2 x 3.14 x 9 ; where π = 3.14

∴ Perimeter = 56.55 in

17

Find the perimeter of given Trapezoid

5 in10 in9 in4 in

Perimeter = 28 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

side 1 = 5 in

side 2 = 10 in

side 3 = 9 in

side 4 = 4 in

Perimeter = 5 + 10 + 9 + 4

∴ Perimeter = 28 in

side 1 = 5 in

side 2 = 10 in

side 3 = 9 in

side 4 = 4 in

Perimeter = 5 + 10 + 9 + 4

∴ Perimeter = 28 in

18

Find the perimeter of given Rectangle

5 in2 in5 in2 in

Perimeter = 14 in

Solution

Perimeter of a Rectangle = 2(l+b)

Length (l) = 5 in

Breadth (b) = 2 in

Perimeter = 2 x (5 + 2)

∴ Perimeter = 14 in

Length (l) = 5 in

Breadth (b) = 2 in

Perimeter = 2 x (5 + 2)

∴ Perimeter = 14 in

19

Find the perimeter of given Parallelogram

4 in2 in4 in2 in

Perimeter = 12 in

Solution

Perimeter of the shape = Sum of the measure of all the sides

side 1 = 4 in

side 2 = 2 in

side 3 = 4 in

side 4 = 2 in

Perimeter = 4 + 2 + 4 + 2

∴ Perimeter = 12 in

side 1 = 4 in

side 2 = 2 in

side 3 = 4 in

side 4 = 2 in

Perimeter = 4 + 2 + 4 + 2

∴ Perimeter = 12 in

20

Find the perimeter of given Square

10 in10 in10 in10 in

Perimeter = 40 in

Solution

Perimeter of a square = 4 x side

side = 10 in

Perimeter = 4 x 10

∴ Perimeter = 40 in

side = 10 in

Perimeter = 4 x 10

∴ Perimeter = 40 in

Find the area & perimeter of 2d shapes (square, rectangle, triangle, circle & more) worksheet with answers for 6th grade math curriculum is available online for free in printable and downloadable (pdf & image) format. Tap on PRINT, PDF or IMAGE button to print or download this grade-6 geometry worksheet to practice how to find the area and perimeter of 2-dimensional shapes such as square, rectangle, right angle triangle, circle, parallelogram, trapezoid, rhombus and pentagon.

In this sixth grade 2d geometry worksheet, students are required to find the area and perimeter of 2d-shapes such as circle, right angle triangle, rectangle, square, trapezoid, pentagon and rhombus by applying the appropriate input values in corresponding formulas.
The below is formulas to find the area of

Square = side x side

Rectangle = length x width

Triangle = 1/2 x base x height

Circle = π r^{2}

The below is formulas to find the perimeter of

Square = 4 x side

Rectangle = 2 x (length + width)

Triangle = side 1 + side 2 + side 3

Circle = 2 π r

Trapezoid = side 1 + side 2 + side 3 + side 4

Parallelogram = side 1 + side 2 + side 3 + side 4

Pentagon = 5 x side

Teachers, tutors, parents or students can check or validate the solved questions by using the corresponding answers key which comprises the step by step work on how to find the area and perimeter of square, rectangle, triangle, circle, parallelogram, trapezoid, rhombus and pentagon.

Students, teachers, tutors or parents can generate unlimited set of questions and answers by using this "**NEW WORKSHEET**" button to prepare exam, assignments, classwork or homework problems, or step by step calculation on finding area and perimeter of square, rectangle, triangle, circle, parallelogram, trapezoid, rhombus and pentagon.

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