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Grade
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Date
Questions10
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1

Find the side of a Triangle whose perimeter is 28 in

9 in ? 9 in

Perimeter = 28 in

2

Find the side of a Parallelogram whose perimeter is 18 in

? 3 in6 in3 in

Perimeter = 18 in

3

Find the side of a Pentagon whose perimeter is 15 in

?

Perimeter = 15 in

4

Find the side of a Rectangle whose area is 45 in^{2}

? 5 in

Area = 45 in^{2}

5

Find the side of a Square whose area is 100 in^{2}

?

Area = 100 in^{2}

6

Find the side of a Square whose area is 49 in^{2}

?

Area = 49 in^{2}

7

Find the side of a Rectangle whose area is 60 in^{2}

10 in ?

Area = 60 in^{2}

8

Find the side of a Trapezoid whose perimeter is 18 in

3 in2 in ? 10 in

Perimeter = 18 in

9

Find the Radius of a Circle whose perimeter is 37.68 in^{2}

?

Perimeter = 37.68 in

10

Find the Radius of a Circle whose perimeter is 43.96 in^{2}

?

Perimeter = 43.96 in

Answers Key

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1

Find the side of a Triangle whose perimeter is 28 in

9 in10 in9 in

Perimeter = 28 in

Solution

Perimeter = Sum of the measure of all the sides.

Perimeter = side1 + side2 + side3.

Perimeter = 28 in

side2 = 9 in

side3 = 9 in

To find side3,

side1 = Perimeter - (side2 + side3)

side1 = 28 - (9 + 9)

∴ side1 = 10 in

Perimeter = side1 + side2 + side3.

Perimeter = 28 in

side2 = 9 in

side3 = 9 in

To find side3,

side1 = Perimeter - (side2 + side3)

side1 = 28 - (9 + 9)

∴ side1 = 10 in

2

Find the side of a Parallelogram whose perimeter is 18 in

6 in3 in6 in3 in

Perimeter = 18 in

Solution

Perimeter = Sum of the measure of all the sides.

Perimeter = side1 + side2 + side3 + side4.

Perimeter = 18 in

side1 = 6 in

side2 = 3 in

side4 = 3 in

To find side3,

side3 = Perimeter - (side1 + side2 + side4)

side3 = 18 - (6 + 3 + 3)

∴ side3 = 6 in

Perimeter = side1 + side2 + side3 + side4.

Perimeter = 18 in

side1 = 6 in

side2 = 3 in

side4 = 3 in

To find side3,

side3 = Perimeter - (side1 + side2 + side4)

side3 = 18 - (6 + 3 + 3)

∴ side3 = 6 in

3

Find the side of a Pentagon whose perimeter is 15 in

3 in

Perimeter = 15 in

Solution

pentagon has 5 sides,and all side have equal length

Perimeter = 5 x side

To find side,Perimeter = 15 in∴ = 3 in

Perimeter = 5 x side

To find side,

side =

Perimeter5

side =

155

4

Find the side of a Rectangle whose area is 45 in^{2}

9 in5 in

Area = 45 in^{2}

Solution

To find length,

Area = 45 in^{2}

Breadth (b) = 5 in

Area = l x b

∴ Length (l) = 9 in

Area = 45 in

Breadth (b) = 5 in

Area = l x b

l =

Areab

Length (l) =

455

5

Find the side of a Square whose area is 100 in^{2}

10 in

Area = 100 in^{2}

Solution

To find side,

Area = 100 in^{2}

Area = side^{2}

side = √area

side = √100

∴ side = 10 in

Area = 100 in

Area = side

side = √area

side = √100

∴ side = 10 in

6

Find the side of a Square whose area is 49 in^{2}

7 in

Area = 49 in^{2}

Solution

To find side,

Area = 49 in^{2}

Area = side^{2}

side = √area

side = √49

∴ side = 7 in

Area = 49 in

Area = side

side = √area

side = √49

∴ side = 7 in

7

Find the side of a Rectangle whose area is 60 in^{2}

10 in6 in

Area = 60 in^{2}

Solution

To find breadth,

Area = 60 in^{2}

Length (l) = 10 in

Area = l x b

∴ Breadth (b) = 6 in

Area = 60 in

Length (l) = 10 in

Area = l x b

b =

Areal

Breadth (b) =

6010

8

Find the side of a Trapezoid whose perimeter is 18 in

3 in2 in3 in10 in

Perimeter = 18 in

Solution

Perimeter = Sum of the measure of all the sides.

Perimeter = side1 + side2 + side3 + side4.

Perimeter = 18 in

side1 = 3 in

side3 = 10 in

side4 = 2 in

To find side4,

side2 = Perimeter - (side1 + side3 + side4)

side2 = 18 - (3 + 2 + 10)

∴ side2 = 3 in

Perimeter = side1 + side2 + side3 + side4.

Perimeter = 18 in

side1 = 3 in

side3 = 10 in

side4 = 2 in

To find side4,

side2 = Perimeter - (side1 + side3 + side4)

side2 = 18 - (3 + 2 + 10)

∴ side2 = 3 in

9

Find the Radius of a Circle whose area is 37.68 in^{2}

6 in

Perimeter = 37.68 in

Solution

To find radius,

Perimeter = 37.68 in

Perimeter = 2 x π x r

∴ Radius(r) = 6 in

Perimeter = 37.68 in

Perimeter = 2 x π x r

Radius (r) =

Perimeter2 x π

Radius (r) =

37.682 x 3.14

; where π = 3.14

10

Find the Radius of a Circle whose area is 43.96 in^{2}

7 in

Perimeter = 43.96 in

Solution

To find radius,

Perimeter = 43.96 in

Perimeter = 2 x π x r

∴ Radius(r) = 7 in

Perimeter = 43.96 in

Perimeter = 2 x π x r

Radius (r) =

Perimeter2 x π

Radius (r) =

43.962 x 3.14

; where π = 3.14

Find the missing side of 2d shapes (square, rectangle, triangle & circle) worksheet with answers for 6th grade math curriculum is available online for free in printable and downloadable (pdf & image) format. Tap on PRINT, PDF or IMAGE button to print or download this grade-6 geometry worksheet to practice how to find the missing side of square, rectangle, triangle & circle by using perimeter or area.

In this sixth grade 2d geometry worksheet, students are required to find the missing side of 2d-shapes such as circle, right angle triangle, rectangle and square by using the area or perimeter formulas. Rearrange the below area and perimeter formulas of 2d-shapes to find the missing side of each shapes in the worksheet.
The below is formulas to find the area of

Square = side x side

Rectangle = length x width

Triangle = 1/2 x base x height

Circle = π r^{2}

The below is formulas to find the perimeter of

Square = 4 x side

Rectangle = 2 x (length + width)

Triangle = side 1 + side 2 + side 3

Circle = 2 π r

Trapezoid = side 1 + side 2 + side 3 + side 4

Parallelogram = side 1 + side 2 + side 3 + side 4

Pentagon = 5 x side

Teachers, tutors, parents or students can check or validate the solved questions by using the corresponding answers key which comprises the step by step work on how to find the missing side of square, rectangle, right angle triangle and circle using area or perimeter.

Students, teachers, tutors or parents can generate unlimited set of questions and answers by using this "**NEW WORKSHEET**" button to prepare exam, assignments, classwork or homework problems, or step by step calculation on finding the missing side of square, rectangle, triangle and circle by using area or perimeter of corresponding shape.

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